Circles and Conic Sections
~14 min read
- What: Circles, parabolas, ellipses, and hyperbolas — the four conic sections — along with their standard equations, eccentricities, foci, and key properties tested in NDA Mathematics Paper.
- Why it matters: PYQ data from 2010 to 2025 shows 4–8 questions per NDA sitting spread across circles and conics, making this one of the most consistent high-yield topics in the coordinate geometry block.
- Key fact: Eccentricity (\(e\)) is the single number that classifies every conic — \(e = 0\) for circle, \(e = 1\) for parabola, \(0 < e < 1\) for ellipse, \(e > 1\) for hyperbola.
Circles and conic sections sit at the heart of NDA coordinate geometry. A conic section is formed when a plane cuts a double-napped cone — the angle of the cut determines which curve appears. For the NDA exam, you need to recognise standard forms instantly, apply eccentricity rules, and solve intercept or focal-distance problems within 90 seconds. This page drills every formula and question type drawn from official NDA PYQs from 2010 through 2025.
What This Topic Covers
The NDA Mathematics syllabus groups Circles and Conic Sections under Analytical Geometry (two dimensions). The examinable content includes:
- Standard and general equation of a circle; conditions for the general second-degree equation to represent a circle.
- Circle touching coordinate axes; intercepts on axes; distance between centres of two circles.
- Parabola — standard forms, vertex, focus, directrix, axis, latus rectum, focal distance.
- Ellipse — standard form, major and minor axes, foci, eccentricity (0 < e < 1), sum of focal distances, latus rectum.
- Hyperbola — standard form, transverse and conjugate axes, foci, eccentricity (e > 1), difference of focal distances, rectangular hyperbola.
- Identification of the conic from a general second-degree equation.
This topic links directly to Straight Lines and Cartesian System (tangent conditions, chord problems) and feeds into Three-Dimensional Geometry (analogous quadric surfaces).
Why This Topic Matters
- Circles alone generated 37 questions in the PYQ file (2010–2025); conics added a further 69 questions — that is over 100 PYQs to mine for patterns.
- Formula recall questions (standard form, eccentricity, focal distance) can each be answered in under 30 seconds once you know the template.
- NDA frequently pairs two sub-questions on the same figure (e.g., "find the centre" then "find the radius") — getting the first right guarantees the second.
Exam Pattern & Weightage
The table below is built from the PYQ files. Each year typically holds one NDA I and one NDA II paper; the count column shows questions from both sittings combined.
| Year | Circle Qs | No. | Total |
|---|---|---|---|
| 2010 | 2 | 3 | 5 |
| 2011 | 2 | 4 | 6 |
| 2012 | 0 | 4 | 4 |
| 2013 | 1 | 4 | 5 |
| 2014 | 0 | 7 | 7 |
| 2015 | 2 | 4 | 6 |
| 2016 | 5 | 4 | 9 |
| 2017 | 2 | 4 | 6 |
| 2018 | 2 | 2 | 4 |
| 2019 | 2 | 3 | 5 |
| 2020 | 1 | 2 | 3 |
| 2021 | 3 | 3 | 6 |
| 2022 | 3 | 3 | 6 |
| 2023 | 4 | 7 | 11 |
| 2024 | 4 | 4 | 8 |
| 2025 | 4 | 5 | 9 |
The combined total runs to well over 100 PYQs. The trend since 2022 shows an increase — 2023 produced 11 questions and 2025 produced 9. Never skip this topic in your final revision.
Paired question sets (two items on the same circle or conic) appear regularly — 2014-II, 2016-I, 2021-II, 2023-I, 2024-I all carried two-question linked sets. Solving the first part correctly sets up the second for free marks.
Core Concepts
General Second-Degree Equation — Identifying the Conic
Every conic (and degenerate pair of lines) springs from one mother equation:
Compute the discriminant \(\Delta = abc + 2fgh - af^2 - bg^2 - ch^2\). Then read off the curve from \(h^2\) versus \(ab\):
Circle: \(a = b,\; h = 0\) | Parabola: \(h^2 = ab\)
Ellipse: \(h^2 < ab\) | Hyperbola: \(h^2 > ab\)
Circle — Standard and General Form
A circle with centre (h, k) and radius r has the standard equation:
Expanding gives the general second-degree form:
The general second-degree equation \(ax^2 + 2hxy + by^2 + 2gx + 2fy + c = 0\) represents a circle when \(a = b\) and \(h = 0\). Both conditions must hold simultaneously — this was directly tested in 2010-II and 2011-I.
This form appears when the endpoints of a diameter are given. It was tested in 2018-II.
Circle Touching the Axes
When a circle touches both coordinate axes, its centre is \((r, r)\), \((-r, r)\), \((r, -r)\), or \((-r, -r)\) where \(r\) is the radius. The standard template equation is:
To find \(r\), use any additional constraint — e.g., the centre lies on a given line. In 2010-II: centre on \(x + y = 4\) gives \(r + r = 4\), so \(r = 2\), producing \(x^2 + y^2 - 4x - 4y + 4 = 0\).
Intercept on the x-axis \(= 2\sqrt{g^2 - c}\); intercept on the y-axis \(= 2\sqrt{f^2 - c}\). For the circle \(x^2 + y^2 + 4x - 7y + 12 = 0\) tested in 2019-I, \(g = 2\), \(f = -7/2\), \(c = 12\), giving y-intercept \(= 2\sqrt{49/4 - 12} = 2\sqrt{1/4} = 1\).
Parabola — Standard Forms
The four standard parabolas and their key features:
\(y^2 = -4ax\) (opens left, focus \((-a, 0)\), directrix \(x = a\))
\(x^2 = 4ay\) (opens up, focus \((0, a)\), directrix \(y = -a\))
\(x^2 = -4ay\) (opens down, focus \((0, -a)\), directrix \(y = a\))
Focal distance of any point \(P(x_1, y_1)\) on \(y^2 = 4ax\) equals \(a + x_1\). This was derived and tested in 2011-II. Latus rectum length \(= 4a\) for all four forms.
One parameter \(t\) gives every point on the parabola — useful when a chord, tangent, or focal-chord question hands you two parameters \(t_1, t_2\) instead of coordinates.
Ellipse — Standard Form and Eccentricity
Foci: \((\pm ae, 0)\) | Sum of focal distances \(= 2a\)
Latus rectum length \(= 2b^2/a\)
The sum of focal distances of any point on the ellipse equals the length of the major axis (\(2a\)). This definition appeared in 2011-I, 2012-II, 2015-I, 2019-I, 2020-I, 2023-I, and 2024-II — memorise it cold.
When the latus rectum equals half the minor axis: \(2b^2/a = b\), so \(a = 2b\). Then \(e = \sqrt{1 - b^2/a^2} = \sqrt{1 - 1/4} = \sqrt{3}/2\). This result was tested in both 2010-II and 2012-I.
Hyperbola — Standard Form and Eccentricity
Foci: \((\pm ae, 0)\) | Difference of focal distances \(= 2a\)
Latus rectum length \(= 2b^2/a\)
The only difference between the two formulas is the sign under the square root — a single character that decides the entire conic. Confirm which curve you have before plugging in.
Eccentricity Summary
This classification was directly asked in NDA 2021-I (statement-type question) with all three non-trivial conditions confirmed correct.
How NDA Tests This Topic
NDA uses three recurring templates: (1) give the equation, ask for centre/radius/eccentricity; (2) give a geometric property (touches axis, passes through points), ask for the equation; (3) give a point, ask if it lies inside/outside the conic, or ask for focal distance. Recognising which template a question uses cuts your solution time in half.
Worked Examples
Example 1 — Circle Touching Both Axes (NDA 2010-II)
Find the equation of the circle which touches both axes and has its centre on the line \(x + y = 4\).
- A circle touching both axes in the first quadrant has centre \((r, r)\) and equation $$x^2 + y^2 - 2rx - 2ry + r^2 = 0$$
- Centre \((r, r)\) must lie on \(x + y = 4\), so \(r + r = 4\), giving \(r = 2\).
- Substitute \(r = 2\): $$x^2 + y^2 - 4x - 4y + 4 = 0$$ This is option (b) — correct answer.
Example 2 — Point Inside a Circle (NDA 2013-I)
Which point lies inside a circle of radius 6 and centre \((3, 5)\)?
- A point \((x_0, y_0)\) is inside the circle if \((x_0 - h)^2 + (y_0 - k)^2 < r^2\).
- Test \((0, 1)\): \((0 - 3)^2 + (1 - 5)^2 = 9 + 16 = 25 < 36\). Inside the circle.
- Test \((2, -1)\): \((2-3)^2 + (-1-5)^2 = 1 + 36 = 37 > 36\). Outside.
- Answer: \((0, 1)\) lies inside the circle.
Example 3 — Eccentricity of an Ellipse (NDA 2010-II, 2012-I)
If the latus rectum of an ellipse equals half its minor axis, find the eccentricity.
- Latus rectum \(= 2b^2/a\); minor axis \(= 2b\). Condition: \(2b^2/a = b\), so \(a = 2b\).
- $$e^2 = 1 - \frac{b^2}{a^2} = 1 - \frac{b^2}{4b^2} = 1 - \frac{1}{4} = \frac{3}{4}$$
- Therefore \(e = \sqrt{3}/2\). Answer confirmed in answer key for both 2010-II and 2012-I.
Example 4 — Focal Distance on a Parabola (NDA 2024-I)
In the parabola \(y^2 = 8x\), the focal distance of point P is 8 units. Verify whether P can be \((6, 4\sqrt{3})\).
- Compare \(y^2 = 8x\) with \(y^2 = 4ax\): \(4a = 8\), so \(a = 2\).
- Focal distance formula \(= a + x_1\). For \(P = (6, 4\sqrt{3})\): focal distance \(= 2 + 6 = 8\). Matches the given condition. Statement A is correct.
- Perpendicular distance of P from directrix \(x = -2\): distance \(= 6 - (-2) = 8\). Statement B is also correct.
- Answer: Both A and B are correct.
Example 5 — Foci of an Ellipse and Sum of Distances (NDA 2024-II)
For the ellipse \(4x^2 + 9y^2 = 1\), foci are Q and R. For any point P on the ellipse, find \(PQ + PR\).
- Rewrite: $$\frac{x^2}{1/4} + \frac{y^2}{1/9} = 1$$ so \(a^2 = 1/4\), \(b^2 = 1/9\). Since \(a^2 > b^2\), major axis is along x-axis, \(a = 1/2\).
- Sum of focal distances of any point on an ellipse \(= 2a = 2 \cdot (1/2) = 1\).
- Answer: \(PQ + PR = 1\).
Example 6 — Centre and Radius from Non-Unit Coefficients
Find the centre and radius of the circle \(2x^2 + 2y^2 - 8x + 12y + 8 = 0\).
- The general-form formulas require the coefficients of \(x^2\) and \(y^2\) to be 1. Divide the whole equation by 2: $$x^2 + y^2 - 4x + 6y + 4 = 0$$
- Match with \(x^2 + y^2 + 2gx + 2fy + c = 0\): \(2g = -4 \Rightarrow g = -2\); \(2f = 6 \Rightarrow f = 3\); \(c = 4\).
- Centre \(=(-g,-f)=(2,-3)\); radius \(r=\sqrt{g^2+f^2-c}=\sqrt{4+9-4}=3\).
Example 7 — Eccentricity from a Non-Standard Ellipse
Find the eccentricity of the ellipse \(9x^2 + 16y^2 = 144\).
- Divide by 144 to get the standard form: $$\frac{x^2}{16} + \frac{y^2}{9} = 1$$
- Here \(a^2 = 16\), \(b^2 = 9\). Since \(a > b\), the major axis lies along the x-axis.
- Apply \(e = \sqrt{1 - b^2/a^2} = \sqrt{1 - 9/16} = \sqrt{7}/4\).
Example 8 — Position of a Point Relative to a Circle
Does the point (1, 2) lie inside, on, or outside the circle \(x^2 + y^2 - 4x - 6y + 4 = 0\)?
- Compute \(S_1\) by plugging the point into the LHS: \(S_1 = 1 + 4 - 4 - 12 + 4 = -7\).
- Sign rule: \(S_1 < 0\) means the point is inside; \(S_1 = 0\) means on the curve; \(S_1 > 0\) means outside.
- Here \(S_1 = -7 < 0\), so (1, 2) lies inside the circle.
Exam Shortcuts (Pro-Tips)
Circles and conics reward formula recognition over fresh derivation. The five shortcuts below convert what looks like a 2-minute derivation into a 15-second mental check. Every one of them has appeared in an NDA paper between 2010 and 2025.
Shortcut 1 — Eccentricity Classifier
Read the eccentricity, name the curve. NDA 2021-I asked this as a four-option statement question — full marks for memorising one row.
Bonus: rectangular hyperbola (\(a=b\)) gives \(e=\sqrt{2}\) instantly — tested NDA 2016-II.
Shortcut 2 — Parabola Focus/Directrix by Inspection
For any parabola in standard form, you do not need to derive — read the focus and directrix off the coefficient of 4a:
The sign of the right-hand side decides direction. \(y^2 = 8x\) means \(4a = 8\), so \(a = 2\), focus \((2,0)\), directrix \(x=-2\), latus rectum 8. Focal distance of any point on it = \(a + x_1\).
The sign of \(4a\) controls direction: \(y^2 = +4ax\) opens right, \(y^2 = -4ax\) opens left, \(x^2 = +4ay\) opens up, \(x^2 = -4ay\) opens down. Mis-reading the sign is the single most common parabola error in NDA — always check before reading focus/directrix.
Shortcut 3 — Ellipse and Hyperbola b² Relations
Eccentricity questions on ellipse/hyperbola collapse to one line if you remember which sign sits between a² and b²:
From these: ellipse \(e = \sqrt{1 - b^2/a^2}\), hyperbola \(e = \sqrt{1 + b^2/a^2}\). The single sign difference is the most-tested trap in this topic.
For an ellipse \(\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1\), the major axis lies along x if \(a > b\) and along y if \(b > a\). Always compare \(a^2\) and \(b^2\) before writing the foci as \((\pm ae, 0)\) — orientation reversal flips the foci to \((0, \pm be)\).
Shortcut 4 — Position of a Point (S₁ Sign Test)
To check whether \((x_1, y_1)\) lies inside, on, or outside any conic \(S=0\), plug the point into the LHS and read the sign of the result \(S_1\):
No discriminants, no distance formulas. NDA 2013-I used this exact template for a circle.
Shortcut 5 — Tangency Conditions (Memorise These)
A line \(y = mx + c\) touches a standard conic only when \(c\) satisfies a fixed condition — memorise the three lines below and tangent problems become one-step substitutions:
For tangent at a given point on the conic, use the T = 0 rule: replace \(x^2 \to xx_1\), \(y^2 \to yy_1\), \(x \to (x+x_1)/2\), \(y \to (y+y_1)/2\). The result is the tangent line — no calculus needed.
The asymptotes of the hyperbola \(\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1\) are the straight lines \(y = \pm\frac{b}{a}x\) — obtained by setting the RHS to 0. For a rectangular hyperbola (\(a=b\)) the asymptotes are \(y = \pm x\), perpendicular to each other.
Test Your Circles & Conics Speed
These formulas only stick when you practise them under timed conditions. Take a full NDA mock test and see exactly where you stand before the real exam.
Start Free Mock TestCommon Question Patterns
Pattern 1 — Condition for General Equation to Represent a Circle
The question gives \(ax^2 + 2hxy + by^2 + 2gx + 2fy + c = 0\) and asks the condition for it to be a circle. The answer is always: \(a = b\) and \(h = 0\). Tested in 2010-II and 2011-I with slight wording variations.
Pattern 2 — Radius from General Equation
Convert the general form to standard form by completing the square. For \(4x^2 + 4y^2 - 20x + 12y - 15 = 0\) (tested 2021-I): divide by 4 first to get \(x^2 + y^2 - 5x + 3y - 15/4 = 0\). Then \(g = -5/2\), \(f = 3/2\), \(c = -15/4\). Radius \(= \sqrt{25/4 + 9/4 + 15/4} = \sqrt{49/4} = 7/2 = 3.5\) units.
Pattern 3 — Two Circles Intersecting at Two Distinct Points
If two circles with radii \(r_1\) and \(r_2\) and centre distance \(d\) intersect at two distinct points, then \(|r_1 - r_2| < d < r_1 + r_2\). This gives a range for an unknown radius \(r\). Tested in 2016-I (\(2 < r < 8\)) and 2017-I (\(2 < r < 8\) again for a similar configuration).
Pattern 4 — Sum or Difference of Focal Distances
For an ellipse, sum \(= 2a\) (major axis length). For a hyperbola, difference \(= 2a\) (transverse axis length). NDA tests this as a recall question or as a back-calculation. You will see it almost every year in one form or another.
Pattern 5 — Identifying the Conic from a Given Equation
The equation \(2x^2 - 3y^2 - 6 = 0\) (tested 2019-I) rewrites as \(\frac{x^2}{3} - \frac{y^2}{2} = 1\) — a hyperbola. The equation \(x^2 + 3y = 0\) (tested 2025-II) rewrites as \(x^2 = -3y\), a downward parabola. Always rearrange to match a standard form before labelling.
Pattern 6 — Tangent to a Circle
The distance from the centre of a circle to a tangent line equals the radius. For the line \(x = y + 2\) (or \(x - y - 2 = 0\)) touching \(4(x^2 + y^2) = r^2\) (tested 2015-II), centre is \((0,0)\) and radius is \(r/2\). Distance \(= |0 - 0 - 2|/\sqrt{2} = 2/\sqrt{2} = \sqrt{2} = r/2\), giving \(r = 2\sqrt{2}\).
For a circle \(x^2 + y^2 - 2kx - 2ky + k^2 = 0\), the centre is \((k, k)\) and radius is \(k\). It touches the x-axis at \(P(k, 0)\) and y-axis at \(Q(0, k)\). \(PQ = \sqrt{k^2 + k^2} = k\sqrt{2}\). This exact result appeared in NDA 2025-II — do not mistake \(PQ\) for the diameter.
Preparation Strategy
Week 1 — Circles (Formula Drill)
Write out the standard form, general form, and diameter form from memory every day. Practice converting general equations to standard form (completing the square). Do all 37 circle PYQs from the file in timed 2-minute slots. Focus on: condition for circle, radius calculation, circle touching axes, intercepts on axes.
Week 2 — Parabola and Ellipse
Memorise all four parabola standard forms with their focus and directrix. Derive the focal distance formula \(a + x_1\) at least once by hand so you understand why it works. For ellipses, practise converting non-standard forms (like \(4x^2 + 9y^2 = 1\)) to the \(a^2/b^2\) form immediately. The sum-of-focal-distances property is pure recall — just remember \(2a\).
Week 3 — Hyperbola and Mixed Practice
Hyperbola questions often come with a parametric point such as \((3 \tan \theta, 2 \sec \theta)\) (tested 2021-I). Substitute into \(\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1\) to identify \(a\) and \(b\), then use \(e = \sqrt{1 + b^2/a^2}\). For rectangular hyperbola, \(a = b\) gives \(e = \sqrt{2}\). Run mixed sets of 10 questions (circles + all three conics) in 15 minutes — that is the NDA pace.
Revision Day — Eccentricity Sheet
One day before the exam, review nothing else from this topic except the eccentricity table and the intercept formulas. These are the easiest marks to lose through formula confusion under pressure.
For further coordinate geometry work, see Straight Lines and Cartesian System and Three-Dimensional Geometry. For topics that integrate with conics through calculus, see Limits, Continuity and Differentiability. Also useful: Vector Algebra (position vectors, locus problems) and NDA Maths — Full Subject Index.
Frequently Asked Questions
How many questions come from circles and conic sections in one NDA paper?
Typically 4–8 questions per paper, split across both Paper I sittings. Since 2022, the count has been consistently above 5 per sitting. The 2023 combined total was 11 questions across NDA I and NDA II, making it a heavy year. Budget time accordingly.
What is the condition for a general second-degree equation to represent a circle?
For \(ax^2 + 2hxy + by^2 + 2gx + 2fy + c = 0\) (\(a \ne 0\)) to represent a circle, two conditions must hold simultaneously: \(a = b\) (coefficients of \(x^2\) and \(y^2\) are equal) and \(h = 0\) (no \(xy\) term). This was directly tested in NDA 2010-II and 2011-I.
What is the focal distance of a point on the parabola y² = 4ax?
The focal distance of any point \(P(x_1, y_1)\) on \(y^2 = 4ax\) is \(a + x_1\). This means it equals the perpendicular distance from P to the directrix \(x = -a\), which is a fundamental property of parabolas tested in NDA 2011-II and 2024-I.
What does the eccentricity tell you about a conic?
Eccentricity (\(e\)) classifies the conic: \(e = 0\) gives a circle, \(e = 1\) a parabola, \(0 < e < 1\) an ellipse, and \(e > 1\) a hyperbola. For a rectangular hyperbola \(a = b\) so \(e = \sqrt{2}\). All four classifications appeared in a single NDA 2021-I statement-based question.
How do you find where a circle and a line intersect?
Substitute the line equation into the circle equation and solve the resulting quadratic. The discriminant tells you if they intersect at two points (\(\Delta > 0\)), touch (\(\Delta = 0\)), or do not meet (\(\Delta < 0\)). Alternatively, compare the perpendicular distance from the centre to the line with the radius.
What is the sum of focal distances for an ellipse and the difference for a hyperbola?
For an ellipse \(\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1\) (\(a > b\)), the sum of focal distances of any point on it is \(2a\) (the length of the major axis). For a hyperbola \(\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1\), the difference of focal distances equals \(2a\) (the length of the transverse axis). Both are constants, independent of which point you choose.
How do you identify a conic from an equation like 2x² − 3y² − 6 = 0?
Rearrange to standard form: \(2x^2 - 3y^2 = 6\), so \(\frac{x^2}{3} - \frac{y^2}{2} = 1\). This matches \(\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1\), the standard hyperbola. The key sign is the minus between the two squared terms. This was tested in NDA 2019-I.